void task1_task(void *p_arg)
{
OS_ERR err;
u8 task1_str[]="First task Running!";
while(1)
{
  printf(" 任务1: ");
  LCD_Fill(0,110,239,319,CYAN);
  OSSemPend(&MY_SEM,0,OS_OPT_PEND_BLOCKING,0,&err);
  memcpy(share_resource,task1_str,sizeof(task1_str));
  delay_ms(300);
  printf("%s ",share_resource);
  OSSemPost (&MY_SEM,OS_OPT_POST_1,&err);   
  LED0 = ~LED0;
  OSTimeDlyHMSM(0,0,1,0,OS_OPT_TIME_PERIODIC,&err);   
}
}

task1这个函数中在请求到信号量后，当执行到delay_ms(300);时会不会引发调度函数啊？后面还有个任务二


void task2_task(void *p_arg)
{
OS_ERR err;
u8 task2_str[]="Second task Running!";
while(1)
{
  printf(" 任务2: ");
  LCD_Fill(0,110,239,319,BROWN);
  OSSemPend(&MY_SEM,0,OS_OPT_PEND_BLOCKING,0,&err);
  memcpy(share_resource,task2_str,sizeof(task2_str));
  delay_ms(300);
  printf("%s ",share_resource);
  OSSemPost (&MY_SEM,OS_OPT_POST_1,&err);   
  LED1 = ~LED1;
  OSTimeDlyHMSM(0,0,1,0,OS_OPT_TIME_PERIODIC,&err);  
}
}