STC12C5A48S2控制CD4094+MC1413来驱动继电器,干扰非常大,如何提高稳定性

2019-11-22 15:38发布

<font face="微软雅黑"><font style="font-size:18px">1、<a href="http://www.hqchip.com/app/870" target="_blank" class="relatedlink">继电器</a>控制的设备上电时,4094的STROBE脚会有尖峰出现,当尖峰很大时<a href="http://www.elecfans.com/tags/继电保护/" target="_blank" class="relatedlink">继电</a>器控制就出错</font></font><br> <font face="微软雅黑"><font style="font-size:18px">2、串行数据输出代码如下</font></font><br><p><br></p><pre style="max-width: 100%;"><code class="cpp hljs" codemark="1"><span class="hljs-function"><span class="hljs-keyword">void</span> <span class="hljs-title">Con_OUT_1</span><span class="hljs-params">(UINT8 dat)</span> </span>{ UINT8 i; Con_Dat_1 = <span class="hljs-number">0</span>; Con_Clk_1 = <span class="hljs-number">0</span>; <span class="hljs-keyword">for</span> (i = <span class="hljs-number">0</span>; i < <span class="hljs-number">8</span>; i ++) { IF ((dat & <span class="hljs-number">0x80</span>) == <span class="hljs-number">0x80</span>) Con_Dat_1 = <span class="hljs-number">1</span>; <span class="hljs-keyword">else</span> Con_Dat_1 = <span class="hljs-number">0</span>; Con_Clk_1 = <span class="hljs-number">0</span>; _nop_(); _nop_(); Con_Clk_1 = <span class="hljs-number">1</span>; dat = (dat << <span class="hljs-number">1</span>); } Con_Cs = <span class="hljs-number">0</span>; _nop_(); _nop_(); Con_Cs = <span class="hljs-number">1</span>; _nop_(); _nop_(); Con_Cs = <span class="hljs-number">0</span>; }</code></pre> <p><br></p>
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