双ADC无法通过DMA实现，望高手指教

2019-03-23 19:47发布

站内问答 / STM32/STM8
2262 2 1420
*以下为ADC触发*/
 /* Time base configuration */
 TIM_TimeBaseStructure.TIM_Period = BufferSize-1;
 TIM_TimeBaseStructure.TIM_Prescaler = 0;
 TIM_TimeBaseStructure.TIM_ClockDivision = 0;
 TIM_TimeBaseStructure.TIM_CounterMode = TIM_CounterMode_Up;
 TIM_TimeBaseStructure.TIM_RepetitionCounter=0;
 TIM_TimeBaseInit(TIM2, &TIM_TimeBaseStructure);  /* TIM2 channel2 configuration in PWM mode */
 TIM_OCInitStructure.TIM_OCMode = TIM_OCMode_PWM1;
 TIM_OCInitStructure.TIM_OutputState = TIM_OutputState_Enable;             
 TIM_OCInitStructure.TIM_Pulse = 8;
 TIM_OCInitStructure.TIM_OCPolarity = TIM_OCPolarity_Low;
 //TIM_OCInitStructure.TIM_OCIdleState = TIM_OCIdleState_Set;        
 TIM_OC2Init(TIM2, &TIM_OCInitStructure);  TIM_SelectMasterSlaveMode(TIM8,TIM_MasterSlaveMode_Enable);// 主从模式
 TIM_SelectSlaveMode(TIM2,TIM_SlaveMode_External1); //从模式 上升沿作为计数脉冲
 TIM_ITRxExternalClockConfig(TIM2,TIM_TS_ITR1);  /* DMA1 Channel1 Configuration ----------------------------------------------*/
 DMA_DeInit(DMA1_Channel1);
 DMA_InitStructure.DMA_PeripheralBaseAddr = ADC1_DR_Address;
 DMA_InitStructure.DMA_MemoryBaseAddr = (u32)ADC_1RegularConvertedValueTab;
 DMA_InitStructure.DMA_DIR = DMA_DIR_PeripheralSRC; //外设作为源
 DMA_InitStructure.DMA_BufferSize =32;
 DMA_InitStructure.DMA_PeripheralInc = DMA_PeripheralInc_Disable;
 DMA_InitStructure.DMA_MemoryInc = DMA_MemoryInc_Enable;
 DMA_InitStructure.DMA_PeripheralDataSize = DMA_MemoryDataSize_Word;
 DMA_InitStructure.DMA_MemoryDataSize = DMA_MemoryDataSize_Word;
 DMA_InitStructure.DMA_Mode = DMA_Mode_Normal;
 DMA_InitStructure.DMA_Priority = DMA_Priority_High;
 DMA_InitStructure.DMA_M2M = DMA_M2M_Disable;
 DMA_Init(DMA1_Channel1, &DMA_InitStructure);
   
 /* Enable DMA1 channel1 */
 DMA_Cmd(DMA1_Channel1, ENABLE);   /* ADC1 configuration ------------------------------------------------------*/
 ADC_DeInit(ADC1);
 ADC_InitStructure.ADC_Mode = ADC_Mode_RegSimult;  //ADC1 and ADC2 为同步规则模式
 ADC_InitStructure.ADC_ScanConvMode = DISABLE;   //单通道模式
 ADC_InitStructure.ADC_ContinuousConvMode = ENABLE;  //循换模式
 ADC_InitStructure.ADC_ExternalTrigConv = ADC_ExternalTrigConv_T2_CC2;
 ADC_InitStructure.ADC_DataAlign = ADC_DataAlign_Right;
 ADC_InitStructure.ADC_NbrOfChannel = 1;
 ADC_Init(ADC1, &ADC_InitStructure);      ADC_RegularChannelConfig(ADC1, ADC_Channel_12, 1, ADC_SampleTime_1Cycles5);
 ADC_DMACmd(ADC1, ENABLE); // /* ADC2 configuration ------------------------------------------------------*/
    ADC_DeInit(ADC2);
 ADC_InitStructure.ADC_Mode = ADC_Mode_RegSimult;
 ADC_InitStructure.ADC_ScanConvMode = DISABLE;
 ADC_InitStructure.ADC_ContinuousConvMode = ENABLE;
 ADC_InitStructure.ADC_ExternalTrigConv = ADC_ExternalTrigConv_None;;
 ADC_InitStructure.ADC_DataAlign = ADC_DataAlign_Right;
 ADC_InitStructure.ADC_NbrOfChannel = 1;
 ADC_Init(ADC2, &ADC_InitStructure);
 ADC_RegularChannelConfig(ADC2, ADC_Channel_14, 1, ADC_SampleTime_1Cycles5);  
 /* Enable ADC1 */
 ADC_Cmd(ADC1, ENABLE);
 /* Enable ADC1 reset calibaration register */  
 ADC_ResetCalibration(ADC1);
 /* Check the end of ADC1 reset calibration register */
 while(ADC_GetResetCalibrationStatus(ADC1));
 /* Start ADC1 calibaration */
 ADC_StartCalibration(ADC1);
 /* Check the end of ADC1 calibration */
 while(ADC_GetCalibrationStatus(ADC1));   /* Enable ADC2 */
 ADC_Cmd(ADC2, ENABLE);
 /* Enable ADC2 reset calibaration register */  
 ADC_ResetCalibration(ADC2);
 /* Check the end of ADC1 reset calibration register */
 while(ADC_GetResetCalibrationStatus(ADC2));
 /* Start ADC2 calibaration */
 ADC_StartCalibration(ADC2);
 /* Check the end of ADC1 calibration */
 while(ADC_GetCalibrationStatus(ADC2));  ADC_SoftwareStartConvCmd(ADC1, ENABLE);
 TIM_CtrlPWMOutputs(TIM2, ENABLE); 
 TIM_Cmd(TIM8, ENABLE);
 TIM_Cmd(TIM2, ENABLE);
 DMA_ITConfig(DMA1_Channel1, DMA_IT_TC, ENABLE); 


双ADC无法完成采集,也无法跳DMA中断，不知道什么原因，触发时钟没有问题，就是无法完成AD转换啊。我是利用TIM2_CC2触发的，已经将ADC1设置为TIM2_CC2触发，ADC2为软件触发。ADC时钟使能，ADC端口都已经设置好了。 此帖出自小平头技术问答
友情提示: 此问题已得到解决，问题已经关闭,关闭后问题禁止继续编辑，回答。
2条回答
Li_Lei
2019-03-23 23:25
 精彩回答 2  元偷偷看……0人看过

一周热门 更多>

相关问题