• 对两个连续整数n和n+1，为什么gcd(n,n+1)=1?

Because when n+1 is divided by n then remainder is 1. Therefore 1 is  the GCD of n, n+1  

• 利用费马定理计算3^201 mod 11

Fermat theorem explains a^p-1 =1 mod p, where p is a prime number and a is positive number that is not disvisible by p. 3^201 mod 11= (3^1 mod 11)* (3^200 mod 11) mod 11 =(3^1 mod 11) * (3^10 mod 11)^20 mod 11 By using Fermat's rule a^p-1 =1 mod p = (3^1 mod 11) *(1 mod 11)^20 mod 11 =1* 3 mod 11 =3

• 利用费马定理找一个0~72之间的数a，使得a模73与9^794同余

Fermat's theorem explain a^p-1 = 1 mod p 9^794 mod 73 =(9^720 mod 73) * (9^74 mod 73)  mod 73 =(9^72 mod 73)^10 * (9^74 mod 73) mod 73 By fermat's rule 9^72 mod 73=1 mod 73 =1* (9^74 mod 73) mod 73 =(9^72)mod 73 * 9^2 mod 73 =81mod 73 =8

• 利用费马定理找一个位于0~28之间的数 x，使得 x^85 模29与6 同余

Fermat's theorem explains the following, a^p-1 =1 mod p ,  p is a prime, a is a positive integer  Another alternative form of Fermat's theorem is used in the problem. a^p = a mod p, p is a prime, a is a positive