10的lga次方等于a 所以a的b次方相当于b*lga 得到一个指数gg 然后再求10的gg次方 再乘上10的n-1次方就是要的答案 思路都来自与学姐和大神#include
#include
#include
using namespace std;
long long ks(long long n,long long m)
{
long long ant=1;
while(m>0)
{
if(m&1)//判断是否是偶数
ant*=n%1000;
n=n*n%1000;
m>>=1;//相当于除2
}
return ant;
}
int main()
{
long long a,b,h;
double zhishu1,zhishu2;
ios::sync_with_stdio(false);//取消同步
while(cin>>a>>b)
{
zhishu1=b*1.0*log10(a);
zhishu2=zhishu1-floor(zhishu1);//floor取整运算
h=pow(10.0,zhishu2)*100;
cout<
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