Java多线程实现简单的售票程序

2019-04-14 16:33发布

站内文章 / 模拟电子
10911 0 1364
class="markdown_views prism-atom-one-light"> 设计一个多线程程序如下：设计一个火车售票模拟程序。假如火车站要有100张火车票要卖出，现在有5个售票点同时售票，用5个线程模拟这5个售票点的售票情况 1、要求打印出每个售票点所卖出的票号 2、各售票点不能售出相同票号的火车票 package com.hebust.java.third; import java.util.Random; public class SaleTicket implements Runnable { public int total; public int count; public SaleTicket() { total = 100; count = 0; } public void run() { while (total > 0) { synchronized (this) { if(total > 0) { try { //Thread.sleep(800); Thread.sleep(new Random().nextInt(1000)); } catch (InterruptedException e) { e.printStackTrace(); } count++; total--; System.out.println(Thread.currentThread().getName() + " 当前票号：" + count); } } } } public static void main(String[] args) { SaleTicket st = new SaleTicket(); for(int i=1; i<=5; i++) { new Thread(st, "售票点" + i).start(); } } } 第二种方法 public class MyThread4 extends Thread { public static int tickets = 100; //static不能省 public static String str = new String("哈哈"); //static不能省 private Object obj = new Object(); public void run() { while (true) { synchronized (obj) { if (tickets > 0) { System.out.printf("%s线程正在卖出第%d张票 ", Thread.currentThread().getName(), tickets); --tickets; } else { break; } } } } } public class rain { public static void main(String[] args) { MyThread4 aa1 = new MyThread4(); aa1.start(); MyThread4 aa2 = new MyThread4(); aa2.start(); } }

热门文章