Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 131072/131072 K (Java/Others)
Total Submission(s): 2757 Accepted Submission(s): 1380
Problem Description
soda has a set S with n integers {1,2,…,n}. A set is called key set if the sum of integers in the set is an even number. He wants to know how many nonempty subsets of S are key set.
Input
There are multiple test cases. The first line of input contains an integer T (1≤T≤105), indicating the number of test cases. For each test case:
The first line contains an integer n (1≤n≤109), the number of integers in the set.
Output
For each test case, output the number of key sets modulo 1000000007.
Sample Input
4 1 2 3 4
Sample Output
0 1 3 7
问题链接:
HDU5363 Key Set
问题描述:(略)
问题分析:
可以根据组合计算推导出f(n)=2^(n-1)-1。使用快速模幂计算即可。
程序说明:(略)
参考链接:(略)
题记:(略)
AC的C++语言程序如下:
/* HDU5363 Key Set */
#include
using namespace std;
typedef long long LL;
const LL MOD = 1000000007;
// 快速模幂
LL powmod(LL x, LL n, LL m)
{
LL result = 1;
for(; n; n>>=1) {
if(n & 1) {
result *= x;
result %= m;
}
x *= x;
x %= m;
}
return result;
}
int main()
{
int t;
scanf("%d", &t);
while(t--) {
LL n;
scanf("%lld", &n);
printf("%lld
", powmod(2, n- 1, MOD) - 1);
}
return 0;
}