51单片机 简易加法计算器

2019-04-15 18:45发布

#include typedef unsigned char uchar; typedef unsigned int uint; typedef unsigned long ulong; sbit ADDR0 = P1^0; sbit ADDR1 = P1^1; sbit ADDR2 = P1^2; sbit ADDR3 = P1^3; sbit ENLED = P1^4; sbit KEY_IN_0 = P2^4; sbit KEY_IN_1 = P2^5; sbit KEY_IN_2 = P2^6; sbit KEY_IN_3 = P2^7; sbit KEY_OUT_0 = P2^3; sbit KEY_OUT_1 = P2^2; sbit KEY_OUT_2 = P2^1; sbit KEY_OUT_3 = P2^0; uchar code LEDChar[] = { //数码管显示字符转换表 0xC0, 0xF9, 0xA4, 0xB0, 0x99, 0x92, 0x82, 0xF8, 0x80, 0x90, 0x88, 0x83, 0xC6, 0xA1, 0x86, 0x8E }; uchar LEDBuff[6] = { //数码管显示缓冲区 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF }; uchar code keyCodeMap[4][4] = { //矩阵按键编号到标准键盘键码的映射表 {0x31, 0x32, 0x33, 0x26}, //数字键1、数字键2、数字键3、向上键 {0x34, 0x35, 0x36, 0x25}, //数字键4、数字键5、数字键6、向左键 {0x37, 0x38, 0x39, 0x28}, //数字键7、数字键8、数字键9、向下键 {0x30, 0x1B, 0x0D, 0x27} //数字键0、ESC键、 回车键、 向右键 }; uchar keyState[4][4] = { //全部矩阵按键的当前状态 {1, 1, 1, 1}, {1, 1, 1, 1}, {1, 1, 1, 1}, {1, 1, 1, 1} }; uchar T0RH = 0; uchar T0RL = 0; void ShowNumber(ulong num) { char i; uchar buf[6]; for (i=0; i<6; i++) { buf[i] = num % 10; num /= 10; } for (i=5; i>=0; i--) { if (buf[i] == 0) LEDBuff[i] = 0xFF; else break; } for (; i>=0; i--) LEDBuff[i] = LEDChar[buf[i]]; } void KeyAction(uchar keyCode) { static ulong result = 0; static ulong number = 0; if (keyCode >= 0x30 && keyCode <= 0x39) { number = number * 10 + keyCode - 0x30; ShowNumber(number); } else if (keyCode == 0x26 || keyCode == 0x0D) { result += number; number = 0; ShowNumber(result); } else if (keyCode == 0x1B) { number = 0; result = 0; ShowNumber(number); } } void KeyDriver() { uchar i, j; static uchar backup[4][4] = { {1, 1, 1, 1}, {1, 1, 1, 1}, {1, 1, 1, 1}, {1, 1, 1, 1} }; for (i=0; i<4; i++) for (j=0; j<4; j++) if (keyState[i][j] != backup[i][j]) { if (keyState[i][j] == 0) KeyAction(keyCodeMap[i][j]); backup[i][j] = keyState[i][j]; } } void KeyScan() { static uchar i = 0; static uchar keyBuf[4][4] = { {0xFF, 0xFF, 0xFF, 0xFF}, {0xFF, 0xFF, 0xFF, 0xFF}, {0xFF, 0xFF, 0xFF, 0xFF}, {0xFF, 0xFF, 0xFF, 0xFF} }; uchar j; keyBuf[i][0] = (keyBuf[i][0] << 1) | KEY_IN_0; keyBuf[i][1] = (keyBuf[i][1] << 1) | KEY_IN_1; keyBuf[i][2] = (keyBuf[i][2] << 1) | KEY_IN_2; keyBuf[i][3] = (keyBuf[i][3] << 1) | KEY_IN_3; for (j=0; j<4; j++) { if (keyBuf[i][j] == 0x00) keyState[i][j] = 0; else if (keyBuf[i][j] == 0xFF) keyState[i][j] = 1; } switch (i) { case 0: KEY_OUT_0 = 1; KEY_OUT_1 = 0; break; case 1: KEY_OUT_1 = 1; KEY_OUT_2 = 0; break; case 2: KEY_OUT_2 = 1; KEY_OUT_3 = 0; break; case 3: KEY_OUT_3 = 1; KEY_OUT_0 = 0; break; default : break; } i = ++i & 0x03; } void LEDScan() { static uchar i = 0; P0 = 0xFF; P1 = (P1 & 0xF8) | i; P0 = LEDBuff[i]; if (i < 5) i++; else i = 0; } void SetTimer0(uint ms) { ulong tmp; tmp = 11059326 / 12; tmp = tmp * ms / 1000; tmp = 65536 - tmp; tmp += 28; T0RL = tmp; T0RH = tmp>>8; } void InterruptTimer0() interrupt 1 { TH0 = T0RH; TL0 = T0RL; LEDScan(); KeyScan(); } void main() { EA = 1; ENLED = 0; ADDR3 = 1; TMOD = 0x01; SetTimer0(1); TH0 = T0RH; TL0 = T0RL; ET0 = 1; TR0 = 1; LEDBuff[0] = LEDChar[0]; while (1) { KeyDriver(); } }


我想加一个效果,在按加号的时候同时显示数字和加号,我使用了第二个定时器定时,可是实验结果是中断服务函数执行得太慢了,扫描很慢,看不到连续的画面,效果不好,而且影响下一个按键的判断。。 #include typedef unsigned char uchar; typedef unsigned int uint; typedef unsigned long ulong; sbit ADDR0 = P1^0; sbit ADDR1 = P1^1; sbit ADDR2 = P1^2; sbit ADDR3 = P1^3; sbit ENLED = P1^4; sbit KEY_IN_0 = P2^4; sbit KEY_IN_1 = P2^5; sbit KEY_IN_2 = P2^6; sbit KEY_IN_3 = P2^7; sbit KEY_OUT_0 = P2^3; sbit KEY_OUT_1 = P2^2; sbit KEY_OUT_2 = P2^1; sbit KEY_OUT_3 = P2^0; uchar code LedChar[] = { //数码管显示字符转换表 0xC0, 0xF9, 0xA4, 0xB0, 0x99, 0x92, 0x82, 0xF8, 0x80, 0x90, 0x88, 0x83, 0xC6, 0xA1, 0x86, 0x8E }; uchar LedBuff[6] = { //数码管显示缓冲区 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF }; uchar code KeyCodeMap[4][4] = { //矩阵按键编号到标准键盘键码的映射表 { 0x31, 0x32, 0x33, 0x26 }, //数字键1、数字键2、数字键3、向上键 { 0x34, 0x35, 0x36, 0x25 }, //数字键4、数字键5、数字键6、向左键 { 0x37, 0x38, 0x39, 0x28 }, //数字键7、数字键8、数字键9、向下键 { 0x30, 0x1B, 0x0D, 0x27 } //数字键0、ESC键、 回车键、 向右键 }; uchar keyState[4][4] = { //全部矩阵按键的当前状态 {1, 1, 1, 1}, {1, 1, 1, 1}, {1, 1, 1, 1}, {1, 1, 1, 1} }; uchar code image[] = { 0xFF,0xE7,0xE7,0x81,0x81,0xE7,0xE7,0xFF }; uchar T0RH = 0; uchar T0RL = 0; void showNumber(ulong num){ char i; uchar buf[6]; for(i=0; i<6; i++){ buf[i] = num % 10; num /= 10; } for(i=5; i>=0; i--){ if(buf[i] == 0) LedBuff[i] = 0xFF; else break; } for(; i>=0; i--){ LedBuff[i] = LedChar[buf[i]]; } } void showPicture(){ TR0 = 0; ET0 = 0; ADDR3 = 0; TMOD &= 0x0F; TMOD |= 0x10; TH1 = 0xFF; TL1 = 0xFE; ET1 = 1; TR1 = 1; } void closePicture(){ TR1 = 0; ET1 = 0; ADDR3 = 1; ET0 = 1; TR0 = 1; } void keyAction(uchar keyCode){ static ulong result = 0; static ulong number = 0; static bit flag = 0; if(keyCode >= 0x30 && keyCode <= 0x39){ if(flag == 1){ closePicture(); flag = 0; } number = number * 10 + keyCode - 0x30; showNumber(number); } else if(keyCode == 0x26 || keyCode == 0x0D){ result += number; number = 0; showNumber(result); showPicture(); flag = 1; } else if(keyCode == 0x1B){ if(flag == 1){ closePicture(); flag = 0; } number = 0; result = 0; showNumber(number); } } void keyDriver(){ uchar i, j; static uchar backup[4][4] = { {1, 1, 1, 1}, {1, 1, 1, 1}, {1, 1, 1, 1}, {1, 1, 1, 1} }; for(i=0; i<4; i++){ for(j=0; j<4; j++){ if(keyState[i][j] != backup[i][j]){ if(keyState[i][j] == 0){ keyAction(KeyCodeMap[i][j]); } backup[i][j] = keyState[i][j]; } } } } void keyScan(){ static uchar i = 0; static uchar keyBuf[4][4] = { {0xFF, 0xFF, 0xFF, 0xFF}, {0xFF, 0xFF, 0xFF, 0xFF}, {0xFF, 0xFF, 0xFF, 0xFF}, {0xFF, 0xFF, 0xFF, 0xFF} }; uchar j; keyBuf[i][0] = (keyBuf[i][0] << 1) | KEY_IN_0; keyBuf[i][1] = (keyBuf[i][1] << 1) | KEY_IN_1; keyBuf[i][2] = (keyBuf[i][2] << 1) | KEY_IN_2; keyBuf[i][3] = (keyBuf[i][3] << 1) | KEY_IN_3; for(j=0; j<4; j++) { if(keyBuf[i][j] == 0x00){ keyState[i][j] = 0; } else if(keyBuf[i][j] == 0xFF){ keyState[i][j] = 1; } } switch(i){ case 0: KEY_OUT_0 = 1; KEY_OUT_1 = 0; break; case 1: KEY_OUT_1 = 1; KEY_OUT_2 = 0; break; case 2: KEY_OUT_2 = 1; KEY_OUT_3 = 0; break; case 3: KEY_OUT_3 = 1; KEY_OUT_0 = 0; break; default: break; } i = ++i & 0x03; } void LEDScan(){ static uchar i = 0; P0 = 0xFF; P1 = (P1 & 0xF8) | i; P0 = LedBuff[i]; if(i < 5) i++; else i = 0; } void setTimer0(uint ms){ ulong tmp; tmp = 11059326 / 12; tmp = tmp * ms / 1000; tmp = 65536 - tmp; tmp += 28; T0RL = tmp; T0RH = tmp>>8; } void interruptTimer0() interrupt 1{ TH0 = T0RH; TL0 = T0RL; LEDScan(); keyScan(); } void interruptTimer1() interrupt 3{ static uchar i = 0, j = 0; static bit flag = 1; if(flag){ ADDR3 = 0; P0 = 0xFF; P1 = (P1 & 0xF8) | i; P0 = image[i]; if(i < 7) i++; else{ i = 0; flag = 0; } } else{ ADDR3 = 1; P0 = 0xFF; P1 = (P1 & 0xF8) | j; P0 = LedBuff[j]; if(j < 5) j++; else{ j = 0; flag = 1; } } keyScan(); } void main(){ EA = 1; ENLED = 0; ADDR3 = 1; TMOD = 0x01; setTimer0(1); TH0 = T0RH; TL0 = T0RL; ET0 = 1; TR0 = 1; LedBuff[0] = LedChar[0]; while(1){ keyDriver(); } }