#include<reg51.h>
#define uchar unsigned char
#define uint unsigned int
// #define r0 P1
void xs(uchar nian0,uchar nian1,uchar nian2,uchar nian3,uchar yue0,uchar yue1,uchar ri0,uchar ri1,uchar shi0,uchar shi1,uchar fen0,uchar fen1,uchar miao0,uchar miao1);
uchar code table[]={0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x90};
uchar a,i,nian0,nian1,nian2,nian3,yue0,yue1,ri0,ri1,shi0,shi1,fen0,fen1,miao0,miao1;
void et1();
void dealy(uint);
void main()
{
et1();
while(1)
{
if(a==2);
{
xs(2,0,1,2);
dealy(10);
}
a=0;
if(a==2);
{
xs(0,2,2,7);
dealy(10);
}
}
}
void et0() interrupt 3
{
TH0=(65536-50000)/256;
TL0=(65536-50000)%256;
a++;
}
void et1()
{
TMOD=0x01;
EA=1;
ET0=1;
TR0=1;
TH0=(65536-50000)/256;
TL0=(65536-50000)%256;
}
void xs(uchar nian0,uchar nian1,uchar nian2,uchar nian3,uchar yue0,uchar yue1,uchar ri0,uchar ri1,uchar shi0,uchar shi1,uchar fen0,uchar fen1,uchar miao0,uchar miao1)
{
P2=0xff;
P1=table[nian0];
P2=0xF7;
P2=0xff;
P1=table[nian1];
P2=0xfB;
P2=0xff;
P1=table[nian2];
P2=0xfD;
P2=0xff;
P1=table[nian3];
P2=0xfe;
P2=0xff;
P1=table[yue0];
P2=0xfe;
P2=0xff;
P1=table[yue1];
P2=0xfe;
P2=0xff;
P1=table[ri0];
P2=0xfe;
P2=0xff;
P1=table[ri1];
P2=0xfe;
P2=0xff;
P1=table[shi0];
P2=0xfe;
P2=0xff;
P1=table[shi1];
P2=0xfe;
P2=0xff;
P1=table[fen0];
P2=0xfe;
P2=0xff;
P1=table[fen1];
P2=0xfe;
P2=0xff;
P1=table[miao0];
P2=0xfe;
P2=0xff;
P1=table[miao1];
P2=0xfe;
}
void dealy(uint z)
{
uint x,y;
for(x=0;x<124;x++)
for(y=0;y<z;y++);
}
Build target 'Target 1'
compiling 1.c...
1.C(27): warning C209: '_xs': too few actual parameters
1.C(21): warning C209: '_xs': too few actual parameters
linking...
Program Size: data=39.0 xdata=0 code=286
"1" - 0 Error(s), 2 Warning(s).
此帖出自
小平头技术问答
你看看自己声明的函数里面有几个形参
太少的实参
头次见到这么多参数
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