在51 Keil中如下兩個函數:
Float2Str正常 Bin2Str不正常。
char * Bin2Str(u8 num)
{
u8 str[8];
str[0] = ((num & 0x80) >> 7) + '0';
str[1] = ((num & 0x40) >> 6) + '0';
str[2] = ((num & 0x20) >> 5) + '0';
str[3] = ((num & 0x10) >> 4) + '0';
str[4] = ((num & 0x08) >> 3) + '0';
str[5] = ((num & 0x04) >> 2) + '0';
str[6] = ((num & 0x02) >> 1) + '0';
str[7] = (num & 0x01) + '0';
return (str);
}
char * Float2Str(float num)//<=65.535
{
unsigned int temp;
unsigned char str[8];
temp = (unsigned int)(num*1000);
str[7] = ' ';
str[6] = ' ';
str[5] = temp%10 + '0';
str[4] = temp/10%10 + '0';
str[3] = temp/100%10 + '0';
str[2] = '.';
str[1] = temp/1000%10 + '0';
str[0] = temp/10000%10 + '0';
return str;
}
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对的是这个原因,奇怪的是下面 的那个函数竟然能工作
这个你要看下汇编..有可能你下面那个函数的空间被释放的但是里面的数据还是原来的数据..因为没有新的数据使用到这些空间
//
//http://www.amobbs.com/forum.php?mod=viewthread&tid=5503119&extra=page%3D1%26filter%3Dauthor%26orderby%3Ddateline%26orderby%3Ddateline
//
#include <stdio.h>
#define u8 unsigned char
#define uint unsigned int
uint Bin2Str(u8 num, char * str){
//u8 str[8];
str[0] = ((num & 0x80) >> 7) + '0';
str[1] = ((num & 0x40) >> 6) + '0';
str[2] = ((num & 0x20) >> 5) + '0';
str[3] = ((num & 0x10) >> 4) + '0';
str[4] = ((num & 0x08) >> 3) + '0';
str[5] = ((num & 0x04) >> 2) + '0';
str[6] = ((num & 0x02) >> 1) + '0';
str[7] = (num & 0x01) + '0';
str[8] = 0;
return 8;
}
uint Float2Str(float num, char * str){//<=65.535
uint temp;
//u8 str[8];
temp = (unsigned int)(num*1000);
str[7] = ' ';
str[6] = ' ';
str[5] = temp%10 + '0';
str[4] = temp/10%10 + '0';
str[3] = temp/100%10 + '0';
str[2] = '.';
str[1] = temp/1000%10 + '0';
str[0] = temp/10000%10 + '0';
return 8;
}
int main(void){
char t0[8], t1[8];
uint r = Bin2Str(123, t0);
printf(" Bin2Str() = %s ", t0);
r = Float2Str(65.535, t1);
printf(" Float2Str() = %s ", t1);
return 0;
}
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