照12楼的说法，我之前处理CHAR型标志位也只是让它为0或者1，看来是不会有太大问题的，只是警告而已。

在转换为bit的时候不是按照非零则为1的规律来处理的，而只是取了最低位作为运算的bit位。

true. and it is an incredibly risky / counter-intuitive convention.

that means the following two pieces of code:

1. unsigned char a_ch;
   
2. unsigned char t_bit;
   
3. 
   
4. if (a_ch) a_ch=SOMETHING;

复制代码and

1. unsigned char a_ch;
   
2. unsigned char t_bit;
   
3. 
   
4. t=a_ch;
   
5. if (t) a_ch=SOMETHING;

复制代码will yield totally different execution.

If you look at some of the better compilers, you will notice that most of they don't have a (native) bitfield type. Boolean types are usually implemented as char or int.

For that reason, I do not use any bit types in my code.

millwood0 发表于 2012-4-22 22:21
true. and it is an incredibly risky / counter-intuitive convention.

that means the following two  ...

PICC果然变态，哈哈，以后还真得多加小心。

shandian 发表于 2012-4-22 21:45
在此处，对于一般的C编译器来说，我觉得用||和|效果应该是一样的。只是内部处理顺序不同。||是先把char类 ...

这怎么可能是一样的呢?