ICD2.5仿真烧写PIC18F66K80出现warning信息要求VPP电压低于12V,求教!!

2020-02-08 12:13发布

求教各位大侠,咨询下。我用ICD2.5仿真或者烧写PIC18F66K80这个芯片的时候,MPLAB里选取Programmer-ICD2,跳出如下信息:
ICDWarn0068:  This device has a VPP(max) below the minimum ICD2 VPP level of 12V.  Please ensure that external protection for MCLR is in place.  (Press the Help button for an example circuit or use AC164112 available from microchipDIRECT.com.)
Connecting to MPLAB ICD 2
...Connected
Setting Vdd source to MPLAB ICD 2
Target Device PIC18F66K80 found, revision = Rev 0x0
...Reading ICD Product ID
Running ICD Self Test
...Passed
MPLAB ICD 2 ready for next operation

我看到有警告信息ICDWarn0068,意思好像说是18F66K80这个芯片烧写仿真时候VPP的电压要低于12V才可以。然后我查看了HELP信息,写道:

ICDWarn0068: This device has a Vpp(max) below the minimum ICD 2 Vpp level of 12V. Please ensure that external protection for MCLR is in place. (Press the Help button for an example circuit.)

The MPLAB ICD 2 Vpp voltage generator is capable of driving from 12V to 14 V. The currently selected device has a Vpp (max) rating less than 12V. Protection circuitry is needed to step down the 12V Vpp generated by the MPLAB ICD2 to a level acceptable by the current device. For example:


但是我的ICD2.5输出电压是13V的,好像标准要求就是13V的。各位大侠,我该怎么弄下???万分感谢!!
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9条回答
su_mj000
1楼-- · 2020-02-09 10:57
很多新问世的PIC器件都要求Vpp编程电压低于12V(8~9V)。最简单的方法是:ICD2的Vpp引脚先串联一个270欧的电阻,
再(对地)接一个8V的稳压二极管(我使用三个led)。
boyvvv123
2楼-- · 2020-02-09 16:51
datasheet上的原理图是正解~端口的极限电压比较低。。。可以查看端口max值!
master0722
3楼-- · 2020-02-09 22:00
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