基于下面的代码求大神改一个只用两位数码管显示根据按键显示 01 02 -----一直到15

2019-07-15 08:49发布

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#include<at89x52.h> //头文件
#define uchar unsigned char //宏定义
#define uint unsigned int
uchar key,n,i; //定义变量
uchar code table[]={0xee,0xde,0xbe,0x7e,0xed,0xdd,0xbd,0x7d,0xeb,0xdb,0xbb,0x7b,0xe7,0xd7,0xb7,0x77}; //反转法矩阵键盘的各个按键的计算值
uchar code yin[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x71}; //共阴极数码管显示0~F
void delay(uint i) //延时函数
{
while(i--);
}
void keyscan()
{
uchar l,h,i; //定义局部变量，用l得出低4位的值，用h得出高4位的值
P3=0x0f; //给P3赋值00001111
l=P3&0x0f;
if(l!=0x0f)
{
delay(100);
P3=0x0f;
l=P3&0x0f;
if(l!=0x0f)
h=P3&0xf0;
P3=0xf0; //给P3赋值11110000
h=P3&0xf0; //若有键按下，得出低四位的值
}
key=l+h; //高4位的值与低4位的值相加
for(i=0;i<16;i++)
{
if(key==table[i]) //通过查表得出n的值
n=i;
}
}
void main()
{
while(1)
{
keyscan(); //扫描按键
for(i=0;i<6;i++) //送入位选信号控制数码管
{
P2_6=1;P2_7=0;
P0=yin[n];
P2_6=0;P2_7=1;
switch(i)
{
case 0:P0=0xfe;break;
case 1:P0=0xfd;break;
case 2:P0=0xfb;break;
case 3:P0=0xf7;break;
case 4:P0=0xef;break;
case 5:P0=0xdf;break;
default:break;
}
P2_6=0;P2_7=0;
delay(100);
}
}
}