请问如果ePWM上拉电阻使能的话会有什么后果？

2019-03-24 09:02发布

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TI piccolo手册中“对于可以用作ePWM的输出的引脚，默认内部上拉电阻禁止使能“，请问如果ePWM上拉电阻使能的话会有什么后果？谢谢！

void InitEPwm1Gpio(void)
{
EALLOW;
/* Disable internal pull-up for the selected output pins
for reduced power consumption */
// Pull-ups can be enabled or disabled by the user.
// Comment out other unwanted lines.
GpioCtrlRegs.GPAPUD.bit.GPIO0 = 1; // Disable pull-up on GPIO0 (EPWM1A)
GpioCtrlRegs.GPAPUD.bit.GPIO1 = 1; // Disable pull-up on GPIO1 (EPWM1B)
/* Configure EPWM-1 pins using GPIO regs*/
// This specifies which of the possible GPIO pins will be EPWM1 functional pins.
// Comment out other unwanted lines.
GpioCtrlRegs.GPAMUX1.bit.GPIO0 = 1; // Configure GPIO0 as EPWM1A
GpioCtrlRegs.GPAMUX1.bit.GPIO1 = 1; // Configure GPIO1 as EPWM1B
EDIS;
}
改为
void InitEPwm1Gpio(void)
{
EALLOW;
/* Disable internal pull-up for the selected output pins
for reduced power consumption */
// Pull-ups can be enabled or disabled by the user.
// Comment out other unwanted lines.
GpioCtrlRegs.GPAPUD.bit.GPIO0 = 0 // Enable pull-up on GPIO0 (EPWM1A)
GpioCtrlRegs.GPAPUD.bit.GPIO1 = 0 // Enalbe pull-up on GPIO1 (EPWM1B)
/* Configure EPWM-1 pins using GPIO regs*/
// This specifies which of the possible GPIO pins will be EPWM1 functional pins.
// Comment out other unwanted lines.
GpioCtrlRegs.GPAMUX1.bit.GPIO0 = 1; // Configure GPIO0 as EPWM1A
GpioCtrlRegs.GPAMUX1.bit.GPIO1 = 1; // Configure GPIO1 as EPWM1B
EDIS;
}

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2条回答

1楼-- · 2019-03-24 14:07

< 本帖最后由 dontium 于 2016-8-26 17:18 编辑

人家不使能就算了，你为什么偏偏要让它使能呢？

PWM脚输出有拉能力，也有灌能力，上拉与下拉都是端口的负担。

再者，设置为PWM功能时，整个硬件部分都由IO功能块切换到了PWM功能块那里了，IO功能就失效了

2楼-- · 2019-03-24 15:57

< ：TI_MSP430_内容页_SA7 --> 楼主看看GPIO MUX的功能。