<span style="" >module abc( clk,
rst_n,
spi_clk,
somi,
cs,
simo);
input clk;
input rst_n;
output reg spi_clk;
output cs;
input somi;
output reg simo;
//---------------10MHz to 500KHz divided by 20-----------------------
parameter N = 3'd5;
parameter M = 5'd20;
reg [N-1:0]clk_count;
always@(posedge clk or negedge rst_n)
begin
if(!rst_n)
begin
clk_count <= 5'b0;
spi_clk <= 1'b0;
end
else if(clk_count == M/2-1)
begin
spi_clk <= ~spi_clk;
clk_count <= 5'b0;
end
else
begin
clk_count <= 5'b0;
clk_count <= clk_count+1'b1;
end
end
//---------------------------------------------------------------
// data transfer
reg cs;
reg [7:0]tx;
reg [7:0]txd;
always@ (posedge clk or negedge rst_n)
begin
if(!rst_n)
begin
tx <=8'ha9;
end
else
begin
txd <= tx;
end
end
reg [3:0]ShiftCounter;
// 移位
always@(posedge spi_clk or negedge rst_n)
begin
if(!rst_n)
begin
simo <= 1'bz;
cs <= 1;
end
else if(ShiftCounter == 4'd8)
begin
simo <= 1'bz;
cs <= 1;
end
else
begin
cs <= 0;
end
end
//上升沿处理// transmit data to mcu
always@(posedge spi_clk or negedge rst_n)
if(!rst_n)
begin
ShiftCounter <= 4'd0;
simo <= 1'bz;
end
else if(~cs)
begin
simo <= txd[7-ShiftCounter];
ShiftCounter <= ShiftCounter + 4'd1;
if(ShiftCounter == 4'd8)
ShiftCounter <= 4'd0;
end
endmodule
两次片选拉高之间8个时钟,现在是9个,大家看看是什么问题
-
时序图
begin
simo <= 1'bz;
cs <= 1;
end
0~8 可不就是9个spi_clk 嘛
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