2019-07-17 14:39发布
ljd1436986456 发表于 2012-10-25 09:32 单位阶越: function [x,n] = stepseq(n0,n1,n2) % Generates x(n) = u(n-n0); n1 n2))
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function [x,n] = stepseq(n0,n1,n2)
% Generates x(n) = u(n-n0); n1 <= n,n0 <= n2
% ------------------------------------------
% [x,n] = stepseq(n0,n1,n2)
%
if ((n0 < n1) | (n0 > n2) | (n1 > n2))
error('arguments must satisfy n1 <= n0 <= n2')
end
n = [n1:n2];
%x = [zeros(1,(n0-n1)), ones(1,(n2-n0+1))];
x = [(n-n0) >= 0];
谢了 已经明白了
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